Skip to main content

How can I pass replacement rules to a package-defined function and have it understand their context?


I am writing a package where I would like to be able to pass replacement rules to a function inside the package and have the function manipulate its symbols using those replacement rules. However, I'm having some trouble implementing it.


(I'm rather baffled because the files used to work and no longer do, coinciding with a change from v10 to v10.1. However, I would be surprised if that is actually the cause as I feel the MWE below completely encapsulates the problem and it looks like a language issue, so instead it may be that I ran the files differently in ways that are hard to reconstruct.)


The specific thing I have in mind is this. Make two files, testpackage.m containing


BeginPackage["Test`"];
replace::usage = "Returns var/.rules.";
Begin["`Private`"];
replace[rules_] := ReplaceAll[var, rules]

End[];
EndPackage[];

and testnotebook.nb containing


Needs["Test`", "/path/to/testpackage.m"]

replace[var-> 0]
replace[Test`Private`var -> 0]

Open the notebook file on a fresh session and load the package. I would like the usage replace[var-> 0] to return 0 - that is, I would like replace to be able to tell var to zero itself. However, it returns Test`Private`var, which upon closer examination of the code is in fact a pretty reasonable thing for it to return. The reasonableness of this is compounded by the fact that replace[Test`Private`var -> 0] will return 0 as expected.



As I said, the usage replace[var->0] used to work fine for my bigger package, and indeed it can work fine in some circumstances (which I cannot pin down exactly, and which I have not been able to reproduce in this MWE yet) if the notebook file is opened on the same Mathematica instance (and thus kernel session) as the package file, with the package file (in practice, a .m auto-generated from a notebook) having been used to run the definition of replace.


So: I have some wonky code, which is probably returning the results it needs to but not the results I want it to, and I would like to amend it to return it to the desired behaviour. In particular: is there some way to take the call


ReplaceAll[var, rules]

and make it forget contexts for a minute?


Alternatively, I'm painfully aware of the possibility that this simply means that I've completely misunderstood the concept of contexts, and that what I want simply isn't doable. This would mean that the behaviour I want, for example, can only be produced by e.g. adding the symbol var to the Test` context, such as by adding the line


var::usage = "var is the variable that gets replaced";

below the usage message for replace. I'm reluctant to take such a step as the package is relatively big (and organically grown, so somewhat messy and without comprehensive unit tests, unfortunately) and I'm afraid of breaking something. If there are no shortcuts then I'm OK with it, but I would like to know if there's a hackier way to get the behaviour I want.



Answer




Try


replace[rules_] := ReplaceAll[Global`var, rules]

in your function. Then


replace[var -> 0]
replace[Test`Private`var -> 0]

yields


0
var


as I think you'd like.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...