Skip to main content

graphics - How to generate approximately equally spaced points efficiently


I don't very content with current method.So a better solution is expected still.I hope it meet two conditions in following.




  1. That space is approximately equivalence.

  2. We can control how many points to produce.




v11.1 provides a new function SpherePoints. As the Details



SpherePoints[n] gives exactly equally spaced points in certain cases for small n. In other cases, it places points so they are approximately equally spaced.



Can we achieve the same goal i.e. approximately equally spaced points in an arbitrary 2D Region?



The following is my attempt based on Union:


SeedRandom[1]
region = ConvexHullMesh[RandomReal[1, {100, 2}]];
UniformPts =
Union[RandomPoint[region, 50000],
SameTest -> (EuclideanDistance[#1, #2] < .1 &)];
Show[region, Graphics[Point[UniformPts]]]


Nevertheless, this approach has two weakness:





  1. It is slow with a large number of pre-generated points i.e. the 2nd argument of RandomPoint, while the space won't be uniform enough if I don't pre-generate enough points, here's an example:


    enter image description here




  2. The number of resulting points isn't controllable.





Answer




Annealing


Found this to be an interesting question and immediately I thought it to be a good application for simulated annealing.


Here's a little unoptimized annealing function I wrote. The idea is that your points move around like atoms in random directions but they "cool down" over time and move less and settle into a minimum energy configuration state.


My rules are:



  1. plan a move in a random direction and random distance of maximum length step

  2. move only if the distance to the nearest point increases

  3. move only if the new location is inside the region


Assumes rm is a globally defined RegionMember function.



anneal[pts_, step_] := 
Module[{np, nn, test1, test2, pl, potentialMoves},
pl = Length@pts;
np = Nearest@pts;
nn = np[#, 2][[2]] & /@ pts;
potentialMoves = RandomReal[step, pl]*RandomPoint[Circle[], pl];
test1 =
Boole@Thread[
MapThread[EuclideanDistance[#1, #2] &, {pts, nn}] <
MapThread[

EuclideanDistance[#1, #2] &, {pts + potentialMoves, nn}]];
test2 = Boole[rm /@ (pts + potentialMoves)];
pts + potentialMoves*test1*test2]

Here is an example with 200 pts, 1000 steps and an anneal rate of .995. Initial step should be on the order of the region size:


Clear[x,y];reg=ImplicitRegion[x^2-y^2<=1,{{x,-3,3},{y,-3,3}}];
rm=RegionMember[reg];
pts=RandomPoint[reg,200];
step=1;
Do[pts=anneal[pts,step=.995*step],1000];

Show[RegionPlot[reg],Graphics[{Black,Point/@pts}]]

stippling example


Here is an animation of the process:


enter image description here


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...