list manipulation - How to use Map inside MapThread?

Given this input

lst1 = {{a, b, c}, {d, e, f}};
lst2 = {1, 2};

and the goal is to generate this output

{  {{1, a}, {1, b}, {1, c}}, 
   {{2, d}, {2, e}, {2, f}}
}

Perfect candidate for MapThread So I made this diagram first to figure what the function I want to map should be

So the function to use inside MapThread, needs to also use Map itself (in order to map each item into the other list). So I came up with this:

lst1 = {{a, b, c}, {d, e, f}};
lst2 = {1, 2};
foo[i_, lst_List] := List[i, #] & /@ lst
MapThread[foo[#1, #2] &, {Range[Length@lst2], lst1}]
(*  {  {{1,a}, {1,b}, {1,c}},       {{2,d}, {2,e}, {2,f}}   }  *)

Now here is the question: Is there a way to do the above without having to define an explicit function but using pure function inside MapThread?

I was getting conflict with # mapping. This is sort of the thing I was trying to do, but can't get the syntax right

(*invalid, for illustration only *)

MapThread[ 
 Function[{idx, lst},List[idx, #] & /@ lst] &  ?? ??    ,{Range[Length@lst2],lst1}]

Or if you know of a better approach to do this, that will be fine as well.

Answer

MapThread[Thread[{##}] &, {lst2, lst1}] 

Map[Thread, {lst2, lst1}\[Transpose]]

## is used so Thread gets called like Thread[{1, {a, b, c}}] As MapThread gives two arguments in this case it is equivalent to Thread[{#1, #2}]& and Composition[Thread, List]