Skip to main content

How to change the variables Qi's to Ri's in one or two steps


I was wondering if there is a command in Mathematica to change all the following Qi's to Ri's? For example, change Q1 to R1, Q2 to R2, etc.


 Q1 a1 + Q2 a2 + Q3 a3 + Q4 a4 + Q5 a5 + Q6 a6 + Q7 a7 + Q8 a8 + 
Q9 a9 + Q10 a10 + Q11 a11 + Q12 a12 + Q13 a13 + Q14 a14 + Q15 a15 +
Q16 a16 + Q17 a17 + Q18 a18 + Q19 a19 + Q20 a20 + Q21 a21 + Q22 a22 +
Q23 a23 + Q24 a24 + Q25 a25 + Q26 a26 + Q27 a27 + Q28 a28 +
Q29 a29 + Q30 a30 + Q31 a31 + Q32 a32 + Q33 a33 + Q34 a34 + Q35 a35 +
Q36 a36 + Q37 a37 + Q38 a38 + Q39 a39 + Q40 a40 + Q41 a41 +

Q42 a42 + Q43 a43 + Q44 a44

I could go through and change the Qi's by hand, but I think there should be a more efficient way to do this.


Thank you.



Answer



I believe I would use:


expr = Q1 a1 + Q2 a2 + Q3 a3 + Q4 a4 + Q5 a5 + Q6 a6 + Q7 a7 + Q8 a8 +
Q9 a9 + Q10 a10 + Q11 a11 + Q12 a12 + Q13 a13 + Q14 a14 +
Q15 a15 + Q16 a16 + Q17 a17 + Q18 a18 + Q19 a19 + Q20 a20 +
Q21 a21 + Q22 a22 + Q23 a23 + Q24 a24 + Q25 a25 + Q26 a26 +

Q27 a27 + Q28 a28 + Q29 a29 + Q30 a30 + Q31 a31 + Q32 a32 +
Q33 a33 + Q34 a34 + Q35 a35 + Q36 a36 + Q37 a37 + Q38 a38 +
Q39 a39 + Q40 a40 + Q41 a41 + Q42 a42 + Q43 a43 + Q44 a44;

expr /. S_Symbol :> Symbol @ StringReplace[SymbolName@S, "Q" -> "R"]

Or more restrictively:


rule = "Q" ~~ x : DigitCharacter .. :> "R" <> x;

expr /. S_Symbol :> Symbol @ StringReplace[SymbolName@S, rule]


I feel that operating only on Symbols is cleaner and safer than converting the entire expression to and from a String.




It is not clear to me if you need this, but if you want to do the replacement after (while) Qi's are assigned values you can do it like this:


{Q1, Q2, Q3, Q4, Q5, Q6, Q7, Q8, Q9, Q10, Q11, Q12} = Range@12;

expr = Hold[Q1 a1 + Q2 a2 + Q3 a3 + Q4 a4 + Q5 a5 + Q6 a6 +
Q7 a7 + Q8 a8 + Q9 a9 + Q10 a10 + Q11 a11 + Q12 a12];

expr /. S_Symbol :>

RuleCondition @ Symbol @ StringReplace[SymbolName@Unevaluated@S, "Q" -> "R"]


Hold[R1 a1 + R2 a2 + R3 a3 + R4 a4 + R5 a5 + R6 a6 +
R7 a7 + R8 a8 + R9 a9 + R10 a10 + R11 a11 + R12 a12]

Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....