Skip to main content

graphs and networks - Label multiple edges between same vertices


I have a simple graph with multiple edges between two vertices, say:


Graph[{
Labeled[a -> b, "A"],
Labeled[a -> b, "B"]
}]

Unfortunately, Mathematica labels both edges "A". Graph with multiple edges to same vertices


How can I label both distinct edges? They really both need to point to the same vertex.


Thanks for your help!




Answer



Update 2: Dealing with the issue raised by @Kuba in the comments:


Using the function LineScaledCoordinate from the GraphUtilities package to place the text labels:


Needs["GraphUtilities`"]

labels ={"A", "B", "C", "D", "E", "F"};
i = 1;
Graph[{a -> b, a -> b, a -> b, a -> b, a -> e, e -> b},
EdgeShapeFunction -> ({Text[labels[[i++]], LineScaledCoordinate[#, 0.5]], Arrow@#} &),
VertexLabels->"Name"]


enter image description here


Update: Using EdgeShapeFunction:


labels=Reverse@{"A","B","C","D"};
i=1;
Graph[{a->b,a->b,a->b, a->b},
EdgeShapeFunction->({Text[labels[[i++]],Mean@#],Arrow@#}&)]

enter image description here





Simplest method to convert a Graph g to Graphics is to use Show[g] (see this answer by @becko).


We can post-process Show[g] to modify the Text primitives:


Show[Graph[{Labeled[a->b,"A"],Labeled[a->b,"B"]}]]/. 
Text["A",{x_,y_/; (y<0.)},z___]:>Text["B",{x,y},z]

enter image description here


Or, we can construct a Graph with modified edge directions (and correct labels) and post-process it to change the edge directions:


Show[Graph[{Labeled[a->b,"A"], Labeled[b->a,"B"]}]]/. 
BezierCurve[{{-1.,0.},m__,y_}]:>BezierCurve[{{1.,0.},m,{-1.,0.}}]
(* same picture *)

Comments

Popular posts from this blog

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...