Skip to main content

programming - Modifying a List in a function in place



An example will be most specific:


func[list_, column_] := list[[All, column]] = Map[#*2 &, list[[All, column]]];

This throws errors.


I want to avoid doing something like this:


func2[list_] := Map[#*2 &; list];

list[[All, 2]] = func2[list[[All,2]]]

because nesting a couple of functions raises complexity unnecessarily, the output would have to be reassigned every time.


Thanks in advance.


As a followup, using HoldFirst works fine, but using the so defined function in a Map gives again errors.


The setup is as follows:


create a nested list


testList = Table[Table[{x y, x y 2}, {x, 1,3}], {y,1,3}]

define afunc with HoldFirst Attribute



afunc = Function[{list, col}, list[[All, col]] = Map[# * 2 &, list[[All, col]]], HoldFirst]

and another function using the first


bfunc[nestedList_, col_] := Map[afunc[#, col] &, nestedList]

now, a call to


bfunc[testList, 2]

should alter the 2'nd columns of the nested lists I'd expect, but it instead throws errors


i've tried to set Attribute HoldFirst on this function as well but it didn't work out as expected




Answer



You basically need a pass-by-reference semantics, which in Mathematica can be emulated with Hold-attributes. Add a HoldFirst attribute to your function:


SetAttributes[func,HoldFirst]

and you should be fine. Without it, list evaluates to its value before the assignment is attempted, and since expressions in Mathematica are immutable, you get an error.


To address your question in comments, the one-liner you asked for can be this:


func = Function[{list,column}, 
list[[All, column]] = Map[#*2 &, list[[All, column]]],
HoldFirst
]


Note however that, since this is a pure function, you can not do argument checks as elegantly as you can with patterns, and you can not overload your functions on different arguments as elegantly.


Note also that, while yet another way to do this is to keep your function as it is but rather wrap the first argument in Unevaluated in every function call, I would strongly advise against that. The reason is that it makes the function itself not self-contained, because it has to assume that the user will always remember to use Unevaluated (which it shouldn't), and there is no way to test whether or not the user actually did use it.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...