legending - Changing the inter-item spacing in Legends (version 9 and up)

The legending functionality in versions 9 and higher is much easier to use than the PlotLegends package and other bespoke ways of creating legends in earlier versions. However, the vertical spacing between items is larger than I would like. How can I reduce this spacing?

Changing the LegendMarkerSize option to a smaller number without changing the size specified in the LegendMarkers option just ends up cutting off the graphic. LegendMargins doesn't affect the inter-item spacing, only the space between the whole legend and other items.

PointLegend[{RGBColor[1, 0, 0], RGBColor[0, 0, 1]}, {"Series 1", "Series 2"}, 
 LegendMarkers -> {{"\[FilledCircle]", 20}, {"\[FilledCircle]", 20}}, 
 LegendMarkerSize -> 19, 
 LabelStyle -> {FontFamily -> "Arial", FontSize -> 20}]

enter image description here

Answer

It turns out that the Spacings option does exactly what is needed, even though its use in legend constructs such as PointLegend is not documented, and it shows as red text when you use it in those constructs.

PointLegend[{Red, Blue}, {"Series 1", "Series 2"}, 

 LegendMarkers -> {{"\[FilledCircle]", 20}, {"\[FilledCircle]", 20}}, 
 Spacings -> {0.2, 0.2}, LegendMarkerSize -> 19, 
 LabelStyle -> {FontFamily -> "Arial", FontSize -> 20}]

enter image description here

This continues the tradition of undocumented options and functions in Mathematica.

UPDATE (2): the Spacings option is still marked with red text in version 10.0.1, 10.1 and 10.3 and 11.0.

Comments

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

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plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....

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