Skip to main content

graphics - find the maximum number of not intersecting circles inside an ellipse


$Version


"10.3.0 for Linux x86 (64-bit) (October 9, 2015)"



(Sequel to 98724 and 99345)


(I use codes originally created by Andy Ross, ybeltukov and J.M.).



I am wondering if one can find the maximum number of randomly generated circles inside a given ellipse.


Using the function findPoints defined below


findPoints = 
Compile[{{n, _Integer}, {low, _Real}, {high, _Real}, {minD, _Real}},
Block[{data = RandomReal[{low, high}, {1, 2}], k = 1, rv, temp},
While[k < n, rv = RandomReal[{low, high}, 2];
temp = Transpose[Transpose[data] - rv];
If[Min[Sqrt[(#.#)] & /@ temp] > minD, data = Join[data, {rv}];
k++;];];
data]];


and taking


npts = 150;(*number of points*)
r = 0.03;(*radius of the circles*)
minD = 2.2 r;(*minimum distance in terms of the radius*)
low = 0; (*unit square*)
high = 1;(*unit square*)

ep = With[{a = 2/5, b = 1/2},
BoundaryDiscretizeRegion@

ParametricRegion[(low + high) {1, 1}/2 +
c ({a Cos[t], b Sin[t]} +
r Normalize[Cross[D[{a Cos[t], b Sin[t]}, t]]]), {{c, 0,
1}, {t, 0, 2 \[Pi]}}]];

SeedRandom[159];
pts = Select[findPoints[npts, low, high, minD], RegionMember[ep, #] &];
g2d = Graphics[{Disk[#, r] & /@ pts, Circle[{1/2, 1/2}, {2/5, 1/2}]},
PlotRange -> All, Frame -> True]


we get


enter image description here


and 72 circles (disks) are lying within the ellipse.


pts // Length
(*72*)

Now I increase progressively the number npts.


npts = 160;

SeedRandom[159];

pts = Select[findPoints[npts, low, high, minD],
RegionMember[ep, #] &] // Length
(*80*)

npts = 170;

SeedRandom[159];
Timing[(pts = Select[findPoints[npts, low, high, minD],
RegionMember[ep, #] &] )// Length]
(*{8.23561, 87}*)


npts = 171;
r = 0.03;
minD = 2.2 r;
low = 0;
high = 1;

SeedRandom[159];
Timing[(pts =
Select[findPoints[npts, low, high, minD],

RegionMember[ep, #] &]) // Length]

(*{12.7237, 87}*)

I guess that we have reach a plateau as it is clear below.


    g2d = Graphics[{Disk[#, r] & /@ pts, Circle[{1/2, 1/2}, {2/5, 1/2}]}, 
PlotRange -> All, Frame -> True]

enter image description here


My question now is how we can use Mathematica in order to extract the maximum number of not intersecting circles withing an ellipse?



Thank you very much.



Answer



The problem consists of two questions: how to determine if circle is inside the ellipse and how to maximize the number of circles?


1. Circle is inside the ellipse?


Let us show that the region of possible circle centers are bounded by a parallel curve of degree 8.


ClearAll[x, y, a, b, r];
eq1 = Simplify[RegionDistance[Disk[{0, 0}, {a, b}], {x, y}]^2 == r^2,
x^2/a^2 + y^2/b^2 > 1]

enter image description here



RegionDistance gives distance outside the ellipse, but it doesn't matter now. Now we can eliminate Root:


pointInEllipse[x_, y_, a_, b_] = 1 - x^2/a^2 - y^2/b^2;
circleNotIntersectEllipse[x_, y_, a_, b_, r_] =
FullSimplify@*Subtract @@
Eliminate[{eq1 /. _Root -> q,
FirstCase[eq1, Root[eq_, _] :> eq@q == 0, , ∞]}, q]

enter image description here


The last formula is positive when the circle doesn't intersect the ellipse. Now we can visualize the obtained region for different values of the circle radius


a = 2;

b = 1;
RegionPlot[Evaluate@
Table[circleNotIntersectEllipse[x, y, a, b, r] > 0 &&
pointInEllipse[x, y, a, b] > 0, {r, 0.2, 1, 0.2}], {x, -1.1 a,
1.1 a}, {y, -1.1 b, 1.1 b}, PlotPoints -> 60, Epilog -> Circle[{0, 0}, {a, b}],
AspectRatio -> Automatic]

enter image description here


There are some glitches, but they appear only for unreasonable big values of the radius.




I think that the circle packing is the good starting point


r = 0.1;
{x, y} = Transpose@Join[Tuples@{##}, Tuples@{# + r, #2 + Sqrt[3] r}] &[
Range[-#, #, 2 r], Range[-#, #, Sqrt[3] 2 r]] &@Max[a, b];
RegionPlot[circleNotIntersectEllipse[x, y, a, b, r] > 0 &&
pointInEllipse[x, y, a, b] > 0, {x, -1.1 a, 1.1 a}, {y, -1.1 b, 1.1 b},
PlotPoints -> 60, Epilog -> {Circle[{0, 0}, {a, b}], Point@Transpose@{x, y}},
AspectRatio -> Automatic]

enter image description here



Points inside the blue region show possible circle centers. Now we have to find the best translation and orientation of the circle packing


transform[x0_, 
y0_, φ_] := {{Cos[φ], Sin[φ]}, {-Sin[φ],
Cos[φ]}}.{x, y} + {x0, y0};
inside[x0_, y0_, φ_] :=
UnitStep[circleNotIntersectEllipse[##, a, b, r], pointInEllipse[##, a, b]] & @@
transform[x0, y0, φ]
func[x0_?NumericQ, y0_?NumericQ, φ_?NumericQ] :=
Total@inside[x0, y0, φ];


{x1, y1, φ1} =
NArgMax[func[x0, y0, φ0], {x0, y0, φ0}]
(* {-0.327895, 0.286679, -0.290644} *)

circles =
Pick[Transpose@transform[x1, y1, φ1], inside[x1, y1, φ1], 1];
Length@circles
(* 160 *)

The number of circles is close to the theoretical prediction from Thies Heidecke's answer



Ï€/2/Sqrt[3] a b/r^2
(* 181.38 *)

Finally, we can plot the result packing


Graphics[{Circle[{0, 0}, {a, b}], Lighter@Blue, Disk[#, r] & /@ circles}]

enter image description here


May be there is possibility to insert one or two circles more, but it requires much more advanced technique.


P.S. The order of evaluation matters. For simplicity I omit some scoping constrictions.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

Is there a way to do conditional matrix loop using 'continue'

I have the following: n = 3; m = 5; ww = RandomReal[{0, 0.1}, {n, n}]; uu = RandomReal[{0, 1}, {m, n}]; pp = RandomReal[{0, 1}, {n, n}]; ss = RandomInteger[{0, 5}, {m, n}]; Grid[{{"ww", "uu", "pp", "ss"}, {ww // TableForm, uu // TableForm, pp // TableForm, ss // TableForm}}, Spacings -> {5, 2}, Dividers -> All] where I would like to look at every element of matrix ss and produce a matrix tt , with zeroes at the locations in ss which have zeroes, and in all other positions do the following: tt = (-1/Subscript[ww, m]) Log[(1 - uu)/(Subscript[pp, m - 1])], where Subscript[ww, m] is the value at index of ww matrix and where Subscript[pp, m - 1] is the value at index-1 of pp matrix. So for example if the first value ever read from matrix ss happens to be 2, then value taken from matrix ww would be from the row 2, but from pp would be from row 1. Also how to tell difference between a 0 as a valid value from within the matrix elemen...