Skip to main content

plotting - Python-style plots in Mathematica


I love making plots in Mathematica. And I love to spend a lot of time making high-quality plots that maximize readability and aesthetics. For most cases, Mathematica can make very beautiful images, but when I see Python-seaborn plots I really love the aesthetics. For example, the density-contour plots. Here is a Python-seaborn example:


Python-seaborn image


Python-seaborn image 2


I have spent too many hours trying to recreate this plots in Mathematica with no success. So my question is: Is there a way to recreate the whole style of these plots (at least the two in this question) in Mathematica?


You can check the seaborn page.





The color schemes are one of the things that I manage very bad. I understand that there is some opacity and transparency involved in the colors but I am really really bad at this, so I cannot help very much in this aspect.




Some example data for doing the plots:


data = BinCounts[
Select[RandomReal[
NormalDistribution[0, 1], {10^5,
2}], -3 <= #[[1]] <= 3 && -3 <= #[[2]] <= 3 &], 0.1, 0.1];

This data using ListContourPlot looks like:


Starter data





As requested in the comments I attached a starter code to the second plot:


Defining a Gaussian-like dataset:


data1 = Table[
1.*a E^(-(((-my + y) Cos[b] - (-mx + x) Sin[b])^2/(2 sy^2 +
RandomReal[{0, 1}])) - ((-mx + x) Cos[b] + (-my + y) Sin[
b])^2/(2 sx^2 + RandomReal[{0, 1}])) /. {a -> 1,
my -> -1, mx -> -4, sx -> 2, sy -> 2, b -> 7 π/3}, {x, -10,
10, 1}, {y, -10, 10, 1}];


Defining the plotting function:


Coolplot[data1_] := 
Module[{data, dataf, sx0, sy0, mx0, my0, fm, bsparameters, sigmaplot,
marginal1, marginal2, final, central, c},

data = Table[{x, y, data1[[x, y]]}, {x, 1, Length@data1[[1]]}, {y,
1, Length@data1[[All, 1]]}];
dataf = Flatten[data, 1];
sx0 = Max[Map[StandardDeviation[#[[All, 3]]] &, data]];
sy0 = Max[Map[StandardDeviation[#[[All, 3]]] &, Transpose[data]]];

{mx0, my0} =
Extract[dataf, Position[dataf[[All, 3]], Max[dataf[[All, 3]]]]][[
1, {1, 2}]];
fm = Quiet@
NonlinearModelFit[dataf,
a E^(-(((-my + y) Cos[b] - (-mx + x) Sin[
b])^2/(2 sy^2)) - ((-mx + x) Cos[b] + (-my + y) Sin[
b])^2/(2 sx^2)), {{a, 0.1}, {b, 0}, {mx, mx0}, {my,
my0}, {sx, sx0}, {sy, sy0}}, {x, y}];
bsparameters = fm["BestFitParameters"];

c[t_, n_] := {mx + Cos[b] (n sx Cos[t]) - Sin[b] (n sy Sin[t]),
my + (n sx Cos[t]) Sin[b] + Cos[b] (n sy Sin[t])} /. bsparameters;
sigmaplot[n_, color_] :=
ParametricPlot[c[t, n], {t, 0, 2 π},
PlotStyle -> {Thick, color, Dashed}];



central =
ListContourPlot[dataf, PlotRange -> All /. bsparameters,

ColorFunction -> "DeepSeaColors",
PlotLegends ->
Placed[BarLegend["DeepSeaColors", LegendLayout -> "Row",
LegendMarkerSize -> 390], Below], ImageSize -> 377];
marginal1 =
ListLinePlot[
Transpose[{Reverse@Map[#[[1, 2]] &, Transpose[data]],
Map[Total@#[[All, 3]] &, Transpose[data]]}], Frame -> True,
AspectRatio -> 1/4, PlotRange -> All, InterpolationOrder -> 0,
Filling -> Bottom, ColorFunction -> "DeepSeaColors",

FrameTicks -> {None, Automatic}];
marginal2 =
ListLinePlot[Map[{#[[1, 1]], Total@#[[All, 3]]} &, data],
Frame -> True, AspectRatio -> 1/4, PlotRange -> All,
InterpolationOrder -> 0, Filling -> Bottom,
ColorFunction -> "DeepSeaColors", FrameTicks -> {None, Automatic}];
final =
Graphics[{Inset[
Show[{central, sigmaplot[1, Red](*,Epilog\[Rule]{Arrow[{c[0,
1],.93c[0,1]}],Text[Style[Subscript[σ, 1],Red],.93c[0,

1]]}*)}, PlotRange -> All], {101.5,
20 + 150 + 85 + 10}, {Center, Center}, {150, 170}],
Rotate[Inset[
marginal1, {100 + 24, 150 + 85 + 45}, {Left, Center}, {145,
50}], 3 π/2],
Inset[marginal2, {101, 150 + 85 + 10 + 124}, {Center,
Center}, {148, 40}]}, ImageSize -> 500];
Magnify[final, 1.5]
]


To spawn the plot use:


Coolplot[data1]

Cool plot



Answer



In this answer, I will concentrate on the colors only to create something like this


Mathematica graphics




Copying the colors from python is a very fast way to get similar results. Nevertheless, the best way to understand what's happening is still to read the underlying publication that was used in seaborn:




There, you find exact explanations about what the author intended to create and how he achieved it. The whole point of such color schemes is to get a color gradient that starts from zero brightness (black) and ends in white. In between those two extremes, it tries to give the viewer the impression of a linearly growing brightness.


Making this way from black to white somewhat colorful is not easy, because the human eye has different perceptions for different colors. So what the author does is to choose a way in the rgb-color cube that spirals around the gray-line resulting in a nice color gradient with linearly growing perceived brightness.


Now, you can understand the name of the colors in python: cubehelix because the way inside the color-cube describes a helix around the gray line. Please read the publication.


Taking the essence out of it (eq. 2) and packing it in a Mathematica function gives:


astroIntensity[l_, s_, r_, h_, g_] := 
With[{psi = 2 Pi (s/3 + r l), a = h l^g (1 - l^g)/2},
l^g + a*{{-0.14861, 1.78277}, {-0.29227, -0.90649},
{1.97294, 0.0}}.{Cos[psi], Sin[psi]}]

In short:




  • l ranges from 0 to 1 and gives the color-value. 0 is black, 1 is white and everything between is a color depending on the other settings

  • s is the color direction to start with

  • r defines how many rounds we circle around the gray line on our way to white

  • h defines how saturated the colors are

  • g is a gamma parameters that influences whether the color gradient is more dark or more bright


After calling astroIntensity you have to wrap RGBColor around it, but then, you can use it as color function. Try to play with this here


Manipulate[
Plot[1/2, {x, 0, 1}, Filling -> Axis,

ColorFunction -> (RGBColor[astroIntensity[#, s, r, h, g]] &),
Axes -> False, PlotRange -> All],
{s, 0, 3},
{r, 0, 5},
{h, 0, 2},
{{g, 1}, 0.1, 2}
]

Mathematica graphics


Or play with your example



data = BinCounts[
Select[RandomReal[
NormalDistribution[0, 1], {10^5,
2}], -3 <= #[[1]] <= 3 && -3 <= #[[2]] <= 3 &], 0.1, 0.1];

Manipulate[
ListContourPlot[data,
ColorFunction -> (RGBColor[astroIntensity[1 - #, s, r, h, g]] &),
InterpolationOrder -> 3, ContourStyle -> None],
{s, 0, 3},

{r, 0, 5},
{h, 0, 2},
{{g, 1}, 0.1, 2}
]

Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...