I have quadratic equation like $eq = x2-7*x5^2$ and vector $xx=\{x0,x1,x2,x3,x4,x5,x6,x7,...\}$. I need to do some nice calculations which will give me coefficient $k=7$, $y=x2$ and $x=x5$, so that equation $y=k*x^2$ is the same as my original equation. Eq is a good equation, so finding $k$, $y$ and $x$ is possbile. How can I do this?
Answer
I'm not sure what exactly you want to achieve, but let it be for a start.
eq = x2-7 x5^5
One can extract the list of variables by
xx = Variables[eq]
{x2, x5}
Then, find the list of exponents and coefficients:
rules = CoefficientRules[eq, xx]
{{1, 0} -> 1, {0, 2} -> -7}
The output means that the first coordinate, x2
, has power 1
(that comes from the {1,0}
part) and a coefficient 1
; the second coordinate, x5
, has power 2
and coefficient -7
. (You can add a term like x2 x5
to see how it works.)
That gives a list of rules that one can use to reproduce the initial polynomial eq
with arbitrary variables:
eqNew = FromCoefficientRules[rules, {y, x}]
-7 x^2 + y
I understand that your eq==0
, so
Simplify[eqNew == 0]
7 x^2 == y
Or
y = y /. First@Solve[eqNew == 0, y]
7 x^2
assigns 7 x^2
to y
:
y
7 x^2
but I don't know how general you want it to be and what purposes should it serve.
Comments
Post a Comment