Skip to main content

programming - How to create a multi-selectable setterbar with colored buttons


Background: consider the following code-snippet.


  Dynamic@Grid[

    Table[Setter[Dynamic[idx, (idx = #1) &],
      i*6 + j, 
    Graphics[{Blue, Disk[]}, ImageSize -> 20]], 
    {i, 0, 1}, {j, 6}]]

This code creates two rows of clickable disk images. So if idx=10 is run, the 10th disk looks pressed. I want to make this control multi-selectable. So if idx={1,12} run, the first and last disks look pressed. ( In my application the disks may have different colors, edge properties and opacity. ) - See also: What is an efficient way of selecting multiple colors via Manipulate?


Question: How to create "a multi-selectable setterbar with colored buttons" ? ( preferably based on the snippet above, but not necessarily ).



Answer



Does this provide the functionality you are looking for? Note that a multi-selectable SetterBar is a TogglerBar. The only problem with the latter is that it cannot be partitioned into a multi-row grid. For your particular problem, I would rather use Button instead of Setter:


list = {};

Dynamic@list

Grid[Table[
   DynamicModule[{pressed = False}, With[{idx = i*6 + j},
     Button[Graphics[{Blue, Disk[]}, ImageSize -> 20], 
      pressed = ! pressed; 
      list = If[pressed, Append[list, idx], DeleteCases[list, idx]], 
      Appearance -> Dynamic@If[pressed, "Pressed", Automatic]]]],
   {i, 0, 1}, {j, 6}]]


Mathematica graphics


A somewhat different approach is to concatenate multiple TogglerBars: this has some drawbacks, as the output is always sorted (if not then output order depends on the order of clicks and the order of TogglerBar rows).


TogglerGrid::usage = 
  "TogglerGrid[x, {val.1, val.2, ...}, n] represents a \
TogglerBar-like control (with setting x and with toggler buttons for \
values val.i to include in the list x), but with togglers arranged in \
a grid, with a maximal n elements per row.";

TogglerGrid[var_, ref_] := TogglerGrid[var, ref, Length@ref];
TogglerGrid[Dynamic[var_], list_List, n_] := Module[

   {set, ref = Evaluate@list, temp},
   temp = {} & /@ ref;
   set = TogglerBar[
       Dynamic[temp[[#]], 
        Function[{$x}, temp[[#]] = $x; 
         var = Sort@(Join @@ temp)]], {ref[[#]]}] & /@ 
     Range@Length@ref;
   Grid[
    Partition[set, n, n, {1, 1}, {}],
    Alignment -> {Center, Center},

    Spacings -> {0, 0}]
   ];
TogglerGrid[var_, arg___] := 
  Module[{dummy = var}, TogglerGrid[Dynamic@dummy, arg]];

Test the function:


x = {};
Dynamic@x
TogglerGrid[Dynamic[x], 
 Table[Graphics[{Hue@RandomReal[], Disk[]}, ImageSize -> 20], {10}],

  5]

Mathematica graphics


Comments

Post a Comment

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]
Post a Comment
Read more

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]
Post a Comment
Read more

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....
Post a Comment
Read more