Skip to main content

plotting - ListPlot with plotmarkers determined by point


I am trying to build on a simple example here:



td = Prime[Range[25]]
dsk = Graphics[{Blue, Disk[]}]
ListPlot[td, PlotMarkers -> {dsk, 0.7}]

How can I make Plotmarkers be a function of points being plotted?



Answer



The description in the question suggests that you may really want to use BubbleChart instead of ListPlot.


You want the plot markers to be a function of the points, and that's exactly what BubbleChart is originally meant to do. It's a relatively new function, but I'll describe how to use it for a simple example based on your prime number table.


In a BubbleChart, each data point has three entries: the x and y coordinates of the point at which the marker is supposed to appear, and a "radius" variable r that determines the size and color of the marker.


The shape of the marker is set by the option "ChartElements", and I'll leave that in its default state (which is a disk as you asked for anyway).



This means that in addition to your table


td = Prime[Range[25]];

we need a data table with three entries for each of the 25 points. For the radius of the disks, I'll pretend that I want to make the marker smallest when the prime number is closest to 50:


data = MapIndexed[Join[#2, {#1, Abs[#1 - 50]/50}] &, td] // N

Now let's plot this:


BubbleChart[data]

bubble1



As an additional way of visualizing the data, we can use the third entry in the point's data to change the color of the disks:


BubbleChart[data, ColorFunction -> (Hue[#3/10] &)]

bubble colors


The documentation shows how you can use arbitrary shapes other than disks, too. It also shows that you can combine several data sets in a single plot if desired.


Edit


One additional issue appears in the answer by kguler and motivated Sjoerd's answer (both of which are fine so I upvoted them of course): it's the question of how to plot these data dependent plot markers and then also draw a line through the data.


The answer is actually very simple - and that also means kguler's answer can be used this way: just combine the BubbleChart with a separate ListLinePlot of the same data using Show:


Show[%, ListLinePlot[td]]


show line


That should cover all the possible issues.


Edit 2: using ErrorListPlot


There is another alternative to get individually styled plot markers. This may be useful when you don't need or want the dynamic interactivity that's built into BubbleChart by default. Of course in general it's nice to have tooltips, mouse-over highlighting etc. But it does require enabling dynamic interactivity in the notebook, whereas ListPlot doe not require that.


An approach that's closer to ListPlot in its lack of interactivity would be to use ErrorListPlot, which requires loading the ErrorBarPlots package. The idea is that an ErrorBar is a kind of plot marker, and it obviously is also designed to vary from point to point. Furthermore, it's possible to define custom error bars (including disks) by specifying the option ErrorBarFunction.


Continuing with the above prime number example, the data list can be simplified by leaving out the first index corresponding to the x coordinate.


data1 = data[[All, 2 ;; 3]]

(*
==> {{2., 0.96}, {3., 0.94}, {5., 0.9}, {7., 0.86}, {11.,

0.78}, {13., 0.74}, {17., 0.66}, {19., 0.62}, {23., 0.54}, {29.,
0.42}, {31., 0.38}, {37., 0.26}, {41., 0.18}, {43., 0.14}, {47.,
0.06}, {53., 0.06}, {59., 0.18}, {61., 0.22}, {67., 0.34}, {71.,
0.42}, {73., 0.46}, {79., 0.58}, {83., 0.66}, {89., 0.78}, {97.,
0.94}}
*)

Then I load the package and define a function to create a more or less arbitrary "plot marker" whose size and color are determined by the second number in each tuple of data1, which is passed to the function as a variable err. I also let the rotation angle vary as a function of the x coordinate which is automatically generated here). This is done in errorfunction - and that's where you can do all your own customization (for variety I chose squares instead of disks here):


Needs["ErrorBarPlots`"]


errorfunction[{x_, y_}, err_] := Inset[
Graphics[{
ColorData["Rainbow"][Last[Flatten[List @@ err]]],
Rotate[Rectangle[{-.5, -.5}, {.5, .5}], Pi x/12]
}, PlotRange -> {{-1, 1}, {-1, 1}}],
(* Here comes the positioning and the scaling: *)
{x, y},
Center,
ImageScaled[Last[err]/5]
]


ErrorListPlot[data1, ErrorBarFunction -> errorfunction, PlotMarkers -> ""]

error plot


The actual PlotMarkers should be suppressed so that only the error bars are left to play the role of markers. That's why I added PlotMarkers -> "".


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.