Skip to main content

matrix - Why do ReplaceAll and With give different results?


I expected both results to be $0_3$:


P = RandomReal[1, {3, 3}];

A = MatrixFunction[Sin, t*P] /. t -> 0
B = With[{t = 0}, MatrixFunction[Sin, t*P]]

(* {{-0.362821 - 1.25562 I, 0.288053 + 1.1563 I, 0.107869 + 0.0658492 I},
{0.133223 - 1.20752 I, -0.220254 + 1.22158 I, 0.181178 - 0.148004 I},
{-0.0991967 + 0.526917 I, -0.208297 - 0.517217 I, 0.583075 + 0.0340421 }} *)

(* {{0., 0., 0.}, {0., 0., 0.}, {0., 0., 0.}} *)

Following J.M. comments:



P = RandomReal[1, {3, 3}, MachinePrecision -> 20] (* => A == B *)
P = RandomReal[1, {3, 3}, MachinePrecision -> 10] (* => A == B *)
P = RandomReal[1, {3, 3}, MachinePrecision -> $MachinePrecision] (* => A != B *)
a = $WorkingPrecision; P = RandomReal[1, {3, 3}, MachinePrecision -> a] (* => A == B *)

Also, using SetPrecision A is zero:


P = RandomReal[1, {3, 3}]
A = MatrixFunction[Sin, t*SetPrecision[P, $MachinePrecision]] /. t -> 0

So it's not a misunderstanding of mine, but a peculiar behaviour of MMA.




Answer



BUG FIXED IN V11.1.0, CONFIRMED IN EARLIER VERSIONS


This is really nothing to do with With and ReplaceAll. (In the case of With the substitution t=0 happens first, so the apparent bug is not triggered).


It looks as if Mathematica gives incorrect answers for


MatrixFunction[Sin, t * P]

in almost all cases where P is a machine precision square matrix of size 2 or larger, and t is unassigned. This does not appear to be a precision issue.


For example, define notionally equivalent matrices


P = {{1, 2}, {4, 3}}/4;


Aa = MatrixFunction[Sin, t P];
An = MatrixFunction[Sin, t N[P]];

Compare


Aa /. t -> 0
An /. t -> 0
(* {{0, 0}, {0, 0}} *)
(* {{0.421637, -0.210819}, {0.843274, -0.421637}} *)

Further, compare the notionally equivalent



MatrixFunction[Sin, N[P]]
Aa /. t -> 1.0
An /. t -> 1.0
(* {{0.151392, 0.398796}, {0.797592, 0.550188}} *)
(* {{0.151392, 0.398796}, {0.797592, 0.550188}} *)
(* {{1.08194, -0.0664758}, {0.265903, 0.816033 *)}}

This even occurs when P is real, symmetric, positive definite with integer coefficients.


UPDATED


This appears to be the result of Mathematica choosing an incorrect algorithm in the specific (and probably unusual) case where MatrixFunction is applied to the product of an unassigned variable and a machine precision matrix. The results given appear to be incorrect for all values t and occur in cases where the matrix is well behaved (the Schur and Jordan decompositions computed in machine precision agree closely with their exact values). Computing the results with any finite precision (not machine precision) does not suffer from this problem.



Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

Is there a way to do conditional matrix loop using 'continue'

I have the following: n = 3; m = 5; ww = RandomReal[{0, 0.1}, {n, n}]; uu = RandomReal[{0, 1}, {m, n}]; pp = RandomReal[{0, 1}, {n, n}]; ss = RandomInteger[{0, 5}, {m, n}]; Grid[{{"ww", "uu", "pp", "ss"}, {ww // TableForm, uu // TableForm, pp // TableForm, ss // TableForm}}, Spacings -> {5, 2}, Dividers -> All] where I would like to look at every element of matrix ss and produce a matrix tt , with zeroes at the locations in ss which have zeroes, and in all other positions do the following: tt = (-1/Subscript[ww, m]) Log[(1 - uu)/(Subscript[pp, m - 1])], where Subscript[ww, m] is the value at index of ww matrix and where Subscript[pp, m - 1] is the value at index-1 of pp matrix. So for example if the first value ever read from matrix ss happens to be 2, then value taken from matrix ww would be from the row 2, but from pp would be from row 1. Also how to tell difference between a 0 as a valid value from within the matrix elemen...