Skip to main content

functions - How to Reap data from a ScheduledTask?


Here is an amusing little function mapped over a range just to iterate it. It ignores its argument and works entirely by side-effecting a global variable:


n$ = 1;

Map[(n$ = (n$++) + n$) &, Range[5]]


{3, 7, 15, 31, 63}

Here is a version of the same thing, just using Reap and Sow:


n$ = 1;
Reap[Map[Sow[n$ = (n$++) + n$] &, Range[5]]][[1]]



{3, 7, 15, 31, 63}

Here is a version that evaluates the function in an asynchronous task, capturing the result in a Dynamic (you'll have to key it in to a notebook, or evaluate the SEUploader (courtesy of @halirutan) notebook I linked at the end of this post, to see the variable n$ updating dynamically):


n$ = 1;
Dynamic[n$]
RunScheduledTask[n$ = (n$++) + n$, {0.25, 5}];


63


Clean up the task:


RemoveScheduledTask[ScheduledTasks[]]

Now, here is an attempt to also capture the results in a Reap (notice no semicolon at the end; I want to see the results of the Reap as well as to see the Dynamic):


n$ = 1;
Dynamic[n$]
Reap[RunScheduledTask[Sow[n$ = (n$++) + n$], {0.25, 5}]]


63


{ScheduledTaskObject[7, HoldForm[Sow[n$ = Increment[n$] + n$]], {0.25, 5},
Automatic, True, "AutoRemove" -> False, "EpilogFunction" :> Null,
"TaskGroup" -> "Global`"], {}}

and its cleanup


RemoveScheduledTask[ScheduledTasks[]]

Evidently, the Reap is evaluated too early and the sown results are lost. How can I get the intended results?


Here's the entire notebook, SE-Uploaded (just evaluate the following expression in a fresh notebook):



Import["http://goo.gl/NaH6rM"]["http://i.stack.imgur.com/x1zYS.png"]

Answer



You can't do this that way,


when you evaluate RunScheduledTask you are only sending a held procedure for scheduled evaluation to Kernel. But Reap[expr]:



gives the value of expr together with all expressions to which Sow has been applied during its evaluation.



RunScheduledTask is of course HoldFirst so Sow is not applied at this time.


You can put Reap inside but the you will need also some temporary variable to be able to retrive reaped value from scheduled evaluation.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.