Skip to main content

plotting - How can I get Mathematica to not mis-align plot labels when exporting to pdf without rasterizing the text?


I have this code:


p = ListPlot[Table[Table[{x, m x}, {x, 0, 20000, 100}],
{m, 0.05/20000, 7/20000, (7 - 0.05)/20000/20}],
PlotLabels -> {"a", "asdfdfasfasdfasd", a, a, a, a, a, a, a, a,
"adfsfasda", "aasdfadfsfasdafsdfasd"},
PlotRange -> {Full, {0, 2}}, ImageSize -> 500]

rp = Rasterize[p]
Export["/tmp/foo2-p.pdf", p]
Export["/tmp/foo2-rp.pdf", rp]
Export["/tmp/foo2-p.png", p]
Export["/tmp/foo2-rp.png", rp]

I get the following images:


foo2-p.pdf:


foo2-p.pdf


foo2-rp.pdf:



foo2-rp.pdf


foo2-p.png:


foo2-p.png


foo2-rp.png:


foo2-rp.png


If I rasterize first, or if I export to png, then the long names are horizontally aligned with the other names. However, if I export directly to pdf, then the names are horribly misaligned. How do I fix this issue without rasterizing the labels? And why is Mathematica doing this? (If it's relevant, I'm using Mathematica 11.2.0.0 on Linux x86_64.)




I've noticed that, using ImageMagick to convert the pdfs to pngs to upload them, the plot labels seem to be centered in boxes that are correctly aligned. So I suspect that one way of fixing this could be somehow tricking Mathematica into thinking that the shorter text is longer than it (a la LaTeX's \smash, \rlap, \llap, \phantom, etc).



Answer



I'm coming the the conclusion that pdf export is buggy in computing bounding boxes. I discovered I can fix the offset by adding:



/. Text[v_, Offset[{dx_, dy_}, {x_, y_}], {0, 0}] :>
Text[v, Offset[{14, 0}, {x, y}], {Left, Center}]

(14 is a magic number that comes from inspecting the input form of graphics and looking that the difference between the size of the image as given by Dimensions of the results of Text[] within Graphics[] and the specified dx offset)


So this code seems to work:


p = ListPlot[Table[Table[{x, m x}, {x, 0, 20000, 100}],
{m, 0.05/20000, 7/20000, (7 - 0.05)/20000/20}],
PlotLabels -> {"a", "asdfdfasfasdfasd", a, a, a, a, a, a, a, a,
"adfsfasda", "aasdfadfsfasdafsdfasd"},
PlotRange -> {Full, {0, 2}}, ImageSize -> 500] /.

Text[v_, Offset[{dx_, dy_}, {x_, y_}], {0, 0}] :>
Text[v, Offset[{14, 0}, {x, y}], {Left, Center}]

Addendum: From https://mathematica.stackexchange.com/a/163490/12258, another option which seems to help but not fully solve the problem (see also How does pdf export handle text alignment?) is to include an explicit FontSize:


p = ListPlot[Table[Table[{x, m x}, {x, 0, 20000, 100}],
{m, 0.05/20000, 7/20000, (7 - 0.05)/20000/20}],
PlotLabels -> Map[Style[#1, 10]&,
{"a", "asdfdfasfasdfasd", a, a, a, a, a, a, a, a,
"adfsfasda", "aasdfadfsfasdafsdfasd"}],
PlotRange -> {Full, {0, 2}}, ImageSize -> 500]

Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]