Skip to main content

plotting - Awful styling in MMA10's Plot


Switching to MMA10, I'd want to produce a plot using this code:


pad = 100;
Fig8 =
Plot[{2 p3[x], p2[x]}, {x, 0, 1}, Frame -> True,
PlotStyle -> {{Thick, Black}, {Thick, Dashed, Gray}},
AspectRatio -> 0.6, PlotRange -> All,

FrameLabel -> {{"Froeschlé HE", "Chirikov mLE"}, {"Chirikov mLE", "Froeschlé mLE"}},
PlotLegends ->
Placed[LineLegend[{"Chirikov map", "2D Froeschlé map"},
LegendLabel -> Placed["p(x)", Above],
LegendFunction -> "Frame", LegendMargins -> 1,
LabelStyle -> 5], {0.65, 0.4}],
BaseStyle -> {FontFamily -> "Times"},
FrameTicks -> {{{{0, "0.0"}, {0.2, "0.2"}, {0.4, "0.4"}, {0.6,
"0.6"}, {0.8, "0.8"}, {1.0, "1.0"}}, {{0, "0.0"}, {0.2,
"0.1"}, {0.4, "0.2"}, {0.6, "0.3"}, {0.8, "0.4"}, {1.0,

"0.5"}}}, {{{0, "0.0"}, {0.2, "0.2"}, {0.4, "0.4"}, {0.6,
"0.6"}, {0.8, "0.8"}, {1.0, "1.0"}}, {{0, "0.0"}, {0.2,
"0.1"}, {0.4, "0.2"}, {0.6, "0.3"}, {0.8, "0.4"}, {1.0,
"0.5"}}}}, ImagePadding -> {{pad, pad}, {All, All}}]`

(Feel free to change the functions p2[x] and p3[x] to whatever you want)


This is generally the same approach I used since MMA7 and 'should' look nice. However, the output is unacceptable:


Export["Fig_8.eps",Fig8]

enter image description here



compared to a .pdf file:


Export["Fig_8.pdf",Fig8]


enter image description here


Although I can convert the .pdf to .eps and it still looks ok, but this is not the case. Why does the .eps look so horrible in MMA10?


EDIT


To clarify: I don't want to get back to styling from older versions. I want the labels (axes and legend) not to be padded with randomly distributed spaces, e.g. bottom label should be "Chirikov mLE", not "Chi ri kovm LE" as it is. And the distances between letters in "Froeschle" seem to be too small. Compare the above screen shots from my Exported .eps and .pdf files.


Moreover, reading threads related to the one mentioned by Mr.Wizard, I have an impression that this lack of functionality comes from new underlying mechanism of Export in MMA10. The question is, can anyone figure out a workaround?


EDIT 2


I'm using Scientific Linux 6.



Answer




On some computer systems, the OS & Mathematica seem not handle fonts properly when exporting to EPS. I am not able to check all systems, but it is possible that converting an expression to PDF first and then to EPS might work. Importing the PDF shows that the font glyphs in the image you get have been converted to Mathematica graphics primitives (FilledCurve usually). Exporting the graphics to EPS should work on all systems. The only possible hitch is whether the fonts were rendered properly in the PDF conversion and import.


Code:


Export["Fig_8.eps", First@ImportString[ExportString[Fig8, "PDF"]]]

General-use function:


exportViaPDF[file_String, expr_, opts___?OptionQ] := 
Export[file,
First@ImportString[
ExportString[expr, "PDF", "PDFOptions" /. {opts} /. "PDFOptions" -> {}]],
opts]


It's hard to set defaults for options to Export. See Pass Options to Export[]. On the other Export is very forgiving of options that make no sense. It seems to ignore them.


Side note: In some random testing, I found the default PDF option setting "AllowRasterization" -> Automatic leads to error messages when the expr is 3D graphics (V10.0.1, Mac OSX 10.10.1):



Import::general: Unsupported Shading type 7 >>



But both the True and False settings worked fine. Example:


exportViaPDF["foo.eps", Plot3D[Sin[x y], {x, -2, 2}, {y, -2, 2}],
"PDFOptions" -> {"AllowRasterization" -> True}, ImageSize -> 100]

Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.