Skip to main content

gui construction - How to set the slider width inside Manipulate


I use the code below to visualise the connection between a sine curve and the unit circle, but would like to make the slider wider, so it has at least almost the same with as the image. I have tried to replace ControlType->Slider[] with ControlType -> Slider[ImageSize->800], but this seems to have no effect at all och the resulting graphics. The question is thus how to set the width of the slider inside Manipulate?


Manipulate[
 With[{ar = 1/(2*Pi), o = v - Cos[v]}, 
  Show[Plot[Sin[x], {x, -6*Pi, 6*Pi}, 

    PlotRange -> {{-2*Pi, 2*Pi}, {-1, 1}}, PlotStyle -> {Black}, 
    AxesLabel -> {"v", Sin["v"]}, AspectRatio -> ar],
   ListLinePlot[{{o + Cos[v], 0}, {o + Cos[v], Sin[v]}}, 
    PlotStyle -> {Thick, Black}, AspectRatio -> ar],
   ListLinePlot[{{o + Cos[v], Sin[v]}, {o, 0}}, 
    PlotStyle -> {Dashed, Black}, AspectRatio -> ar],
   Graphics[{AbsolutePointSize[8], Point[{o, 0}]}, AspectRatio -> ar],
   Plot[{-Sqrt[1 - (x - o)^2], Sqrt[1 - (x - o)^2]}, {x, o - 1, 
     o + 1}, PlotRange -> {{-2*Pi, 2*Pi}, {-1, 1}}, 
    PlotStyle -> {{Thick, Orange}, {Thick, Orange}}, 

    AspectRatio -> ar], ImageSize -> 800]], {v, -3/2*Pi, 3/2*Pi}, 
 ControlType -> Slider[]]

The resulting graphics



Answer



You have to study the documentation carefully, but I agree that help-pages like the one of Manipulate are very densely packed with information. In the Details and Options section you find how to set options for controls:



{{u,...},...,opts}    control with particular options

The non-obvious part is, that you have to set the ControlType as well to make this work. Therefore, you can use



{v, -3/2*Pi, 3/2*Pi, ControlType -> Slider, ImageSize -> 800}

to achieve the wanted behavior. Another way is to replace Manipulate by a full DynamicModule which is a bit more code but gives you some more flexibility


DynamicModule[{v = -3/2 Pi, o},
 o = v - Cos[v];
 Panel@
  With[{ar = 1/(2*Pi)},
   Column[{
     Slider[Dynamic[v, (v = #; o = v - Cos[v]; &)], {-2 Pi, 2 Pi}, 
      ImageSize -> 800],

     Dynamic@
      Show[Plot[Sin[x], {x, -6*Pi, 6*Pi}, 
        PlotRange -> {{-2*Pi, 2*Pi}, {-1, 1}}, PlotStyle -> {Black}, 
        AxesLabel -> {"v", Sin["v"]}, AspectRatio -> ar], 
       ListLinePlot[{{o + Cos[v], 0}, {o + Cos[v], Sin[v]}}, 
        PlotStyle -> {Thick, Black}, AspectRatio -> ar],
       ListLinePlot[{{o + Cos[v], Sin[v]}, {o, 0}}, 
        PlotStyle -> {Dashed, Black}, AspectRatio -> ar], 
       Graphics[{AbsolutePointSize[8], Point[{o, 0}]}, 
        AspectRatio -> ar], 

       Plot[{-Sqrt[1 - (x - o)^2], Sqrt[1 - (x - o)^2]}, {x, o - 1, 
         o + 1}, PlotRange -> {{-2*Pi, 2*Pi}, {-1, 1}}, 
        PlotStyle -> {{Thick, Orange}, {Thick, Orange}}, 
        AspectRatio -> ar], ImageSize -> 800, Background -> White]
     }]
   ]]

enter image description here


Comments

Post a Comment

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]
Post a Comment
Read more

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]
Post a Comment
Read more

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.
Post a Comment
Read more