graphics3d - Extruding a weird 2D shape to make a prismatic 3D shape

I have the outline of a 2D shape defined by a periodic radius R[θ]. I would like to extrude this linearly to a prismatic 3D object that has my cross-sectional shape. I could extrude the outline, as shown below, but I need it to be filled, or at least capped. It would have been nice if I could use the Tube Graphics3D option and specify the radius as a function of theta. There must be a simple way to do this. Any suggestions ?

shape = PolarPlot[R[θ], {θ, 0, 2 π}, Axes -> False,
     PlotStyle -> {Black, Thickness[0.02]}]

shape3d = ParametricPlot3D[{R6[θ] Cos[θ], R6[θ] Sin[θ], z}, {θ, 0, 2 π}, {z, -2, 5}, 
     Axes -> False, Boxed -> False, Mesh -> None] 

Answer

Michael Seifert's answer is the easiest for curves that can be plotted parametrically, but there is a slightly more general method that can be used to construct an extrusion of any curve that can be plotted in 2D.

First, note that one can always extract the points from a 2D plotted curve, because Mathematica never forgets. For instance, with the curve provided in the question:

R[θ_] := (1 + 0.5 Sin[2 θ]);
shape1 = PolarPlot[R[θ], {θ, 0, 2 π}, 
  Axes -> False, 
  PlotStyle -> {Orange, Thickness[0.02]}
 ];

the points are located via

points = (Flatten @ shape1[[1]])[[2, 1]]

Other information about the curve can be found similarly, and using that info and list manipulations, we can use Polygons to construct a surface. Here is an extrusion function that does what is necessary:

Options[Extrude] = Join[Options[Graphics3D], {Closed -> True, Capped -> True}];

Extrude[curve_, {zmin_, zmax_}, opts : OptionsPattern[]] := 
  Module[{info, points, color, tube, caps},
   info = Flatten @ {curve[[1]]};
   points = Select[info, Head[#] === Line &][[1, 1]];

   If[OptionValue[Closed], points = points ~Join~ {points[[1]]}];
   color = Select[info, Head[#] === Directive &];
   If[Length[color] == 0, color = Orange, color = First @ Select[color[[1]], ColorQ]];

   tube = Polygon[
     Partition[
      Flatten[
       Transpose[points /. {x_, y_} -> {x, y, #} & /@ {zmin, zmax}], 1], 3, 1]
    ];


   If[OptionValue[Closed] && OptionValue[Capped],
    caps = Polygon[points /. {x_, y_} -> {x, y, #}] & /@ {zmin, zmax};
    tube = Flatten@{tube, caps},
    tube = {tube}
   ];

   Graphics3D[
    Flatten @ {EdgeForm[None], color, #} & /@ tube,
    FilterRules[{opts}, Options[Graphics3D]]
   ]

  ];

For the case in hand, we get

Extrude[shape1, {-2, 5}, Boxed -> False]

This is really a lot of work for the same result that Michael's answer gives more easily, but we can use this to close and extrude any plotted 2D curve:

shape2 = Plot[x^2, {x, -2, 2}, Axes -> False]
Extrude[shape2, {-2, 5}, Boxed -> False]

This will not work with Graphics primitives, as they do not provide a list of points that can be extracted (well, it will work with a Graphics[Line[...]]). Also, to close a non-closed shape, it simply connects the first and last points, which might not be the behavior always desired. Lastly, note that one can leave the caps off:

shape3 = Graphics[
  Line[{{0, 0}, {1, 1}, {2, -1}, {3, 0}, {4, -2}, {5, 1}, {-1, 2}, {0, 0}}]]
Extrude[shape3, {-2, 5}, Capped -> False, Boxed -> False]