Skip to main content

functions - Why is the new PositionIndex horribly slow?


This issue has largely been mitigated in 10.0.1. New timings for the final test below are:


Needs["GeneralUtilities`"]
a = RandomInteger[9, 5*^5];
myPosIdx[a] // AccurateTiming
cleanPosIdx[a] // AccurateTiming (* see self-answer below *)

PositionIndex[a] // AccurateTiming


0.0149384

0.0149554

0.0545865

Still several times slower here than the readily available alternatives but no longer devastating.





Disconcertingly I have discovered that the new (v10) PositionIndex is horribly slow.


Using Szabolcs's clever GatherBy inversion we can implement our own function for comparison:


myPosIdx[x_] :=
<|Thread[x[[ #[[All, 1]] ]] -> #]|> & @ GatherBy[Range @ Length @ x, x[[#]] &]

Check that its output matches:


RandomChoice[{"a", "b", "c"}, 50];

myPosIdx[%] === PositionIndex[%]



True

Check performance in version 10.0.0 under Windows:


a = RandomInteger[99999, 5*^5];
myPosIdx[a] // Timing // First
PositionIndex[a] // Timing // First



0.140401

0.920406

Not a good start for the System` function, is it? It gets worse:


a = RandomInteger[999, 5*^5];
myPosIdx[a] // Timing // First
PositionIndex[a] // Timing // First



0.031200

2.230814

With fewer unique elements PositionIndex actually gets slower! Does the trend continue?


a = RandomInteger[99, 5*^5];
myPosIdx[a] // Timing // First
PositionIndex[a] // Timing // First



0.015600

15.958902

Somewhere someone should be doing a face-palm right about now. Just how bad does it get?


a = RandomInteger[9, 5*^5];
myPosIdx[a] // Timing // First
PositionIndex[a] // Timing // First



0.015600

157.295808

Ouch. This has to be a new record for poor computational complexity in a System function. :o



Answer



First let me note that I didn't write PositionIndex, so I can't speak to its internals without doing a bit of digging (which at the moment I do not have time to do).


I agree performance could be improved in the case where there are many collisions. Let's quantify how bad the situation is, especially since complexity was mentioned!


We'll use the benchmarking tool in GeneralUtilities to plot time as a function of the size of the list:


Needs["GeneralUtilities`"]

myPosIdx[x_] := <|Thread[x[[#[[All, 1]]]] -> #]|> &@
GatherBy[Range@Length@x, x[[#]] &];
BenchmarkPlot[{PositionIndex, myPosIdx}, RandomInteger[100, #] &, 16, "IncludeFits" -> True]

which gives:


PositionIndex benchmark


While PositionIndex wins for small lists (< 100 elements), it is substantially slower for large lists. It does still appear to be $O(n \log n)$, at least.


Let's choose a much larger random integer (1000000), so that we don't have any collisions:


enter image description here


Things are much better here. We can see that collisions are the main culprit.



Now lets see how the speed for a fixed-size list depends on the number of unique elements:


BenchmarkPlot[{PositionIndex, myPosIdx}, RandomInteger[#, 10^4] &, 
2^{3, 4, 5, 6, 7, 8, 9, 10, 11, 12}]

enter image description here


Indeed, we can see that PositionIndex (roughly) gets faster as there are more and more unique elements, whereas myPosIdx gets slower. That makes sense, because PositionIndex is probably appending elements to each value in the association, and the fewer collisions the fewer (slow) appends will happen. Whereas myPosIdx is being bottlenecked by the cost of creating each equivalence class (which PositionIndex would no doubt be too, if it were faster). But this is all academic: PositionIndex should be strictly faster than myPosIdx, it is written in C.


We will fix this.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...