Skip to main content

variable definitions - Can I create a dynamic number of rows in TabView through an iteration?


I have written code, with the help of stackoverflow of course, and I want to make it user friendly so that other people in my lab can use it. I'm playing with DialogCreate and similar functions. I want to do something like this so far:


   CreateDialog[TabView[{
"General" ->
Column[{
Row[{TextCell["Project Name:"], InputField[Dynamic[Project]]}],
Row[{TextCell["Number of Wells:"], InputField[Dynamic[num]],
Button["Set", DialogReturn[num]]}]}],
"Row Selection" ->
Column[{Do[

Row[TextCell["Well " <> ToString[i] <> ":"],
FileNameSetter[Dynamic[Evaluate[Symbol["w" <> ToString[i]]]],
"Open"]], {i, 1, num}]}]}, ControlPlacement -> Left]
]

I want to dynamically create more rows based on the input of "Number of Wells" within the same dialogbox but in a different tab. Is anything like this possible or some sort of alternative?



Answer



CreateDialog[
TabView[
{"General" ->

Column[{Row[{"Project Name:", InputField[Dynamic[project]]}],
Row[{"Number Of Wells:", InputField[Dynamic[num]],
Button["Set", DialogReturn[num]]}]}],
"Row Selection" ->
Dynamic@Column[
Table[Row[{"Well " <> ToString[i] <> ":",
FileNameSetter[Dynamic[Evaluate[Symbol["w" <> ToString[i]]]],
"Open"]}], {i, 1, num}]]},
ControlPlacement -> Left]]


enter image description here


Update: There are two problems in the original code:


First, regarding the use of Do, unless an explicit Return is used, the value returned by Do is Null. Please see the docs on Do and the tutorial Loops and control structures. For example


 t = 2; Do[t = 1 + k t, {k, 1, 2}]

does the calculation to change the value of t but does not return anything. You need to explicitly call the new value of t to see the effect of what happened inside Do:


t = 2; Do[t = 1 + k t, {k, 1, 2}];t
(* which gives the result: 7 *)

So, to get your code working with Do, you need to do something like:



"Row Selection" -> 
Dynamic@Column[tt = {};
Do[AppendTo[tt, Row[{"Well " <> ToString[i] <> ":",
FileNameSetter[Dynamic[Evaluate[Symbol["w" <> ToString[i]]]],
"Open"]}]],
{i, 1, num}]; tt]

which, of course, is not as clean as the alternative with Table[...].


Second, regarding why Dynamic[Column[ ...]] is needed please see the tutorial Introduction to Dynamic, in particular, the section Where Should Dynamic Be Placed in an Expression?


By the way, @ is short form of Prefix, and f@x is an alternative syntax for f[x], that is, Dynamic@Column[.....] is the same as Dynamic[Column[...]].



Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.