Skip to main content

plotting - Why is my plot cut off?


I am trying to use Show to combine two plots so I do the following:


g1 = Plot[x, {0, 100}, AspectRatio -> 1]
g2 = ListContourPlot[data, FrameLabel -> {"label1", "label2"}, 
  PlotLabel -> "title", AspectRatio -> 1, 

  DataRange -> {{0, 100}, {0, 100}}]

g3 = Show[{g1, g2}]

Everything looks great on the computer.


Now, I want to export.


Export[g3, "test.pdf", ImageResolution -> 600]

This creates a problem. The y-axis label is completely missing. The image is cut off on the left-hand side. It's not white space or anything like that. It's just not there. The whole left side of the image is missing. The title of the plot is partially cut off too.


How do I fix this?




Answer



If you fix the syntax errors in Plot and Export, and change the ordering of the two graphics in Show everything works fine. The source of problem you are having is: Show uses the options from the first graphics object, and automatic values of image padding for your g1 does not leave space for the frame labels of g2 to show. So, the following minor changes in your code should fix the problem.


  g1 = Plot[x, {x, 0, 100}, AspectRatio -> 1] ;

  g2 = ListContourPlot[data, FrameLabel -> {"label1", "label2"}, 
  PlotLabel -> "title", AspectRatio -> 1, 
  DataRange -> {{0, 100}, {0, 100}}] ;

  g3 = Show[{g2, g1}]


  Export["test.pdf", g3, ImageResolution -> 600]

produces the correct pdf file that shows the frame labels.


Notes:



Everything looks great on the computer.

Not quite... With Show[{g1,g2}] you get the following on the screen:


Show(g1g2)


where



 data = RandomReal[{0, 10}, {20, 2}];

is used as data input for ListContourPlot.


Using Show[{g2,g1}] you get:


enter image description here


Finally, although the resulting pdf file shows the plot and frame labels


pdf export file


you probably still want to play with various values for ImagePadding as Szabolcs suggests to adjust the spaces on the four sides of the graph.


Comments

Post a Comment

Popular posts from this blog

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...
Post a Comment
Read more

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...
Post a Comment
Read more

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more