Skip to main content

graphs and networks - Strategies for solving problems involving searches


As an example of a search-oriented problem, consider finding all constrained $n$-colorings of a graph. An "$n$-coloring" associates one of $n \ge 1$ colors to each vertex in such a way that no edge connects vertices of the same color. A "constrained" coloring requires that certain vertices have certain fixed colors.


For instance, here is a graph with one of its vertices already colored red; the default (cyan) vertices are as yet uncolored:


Partial coloring of a graph


There are 10 ways to color this graph using three colors; say, {red, green, blue}, while keeping the red vertex red:


All constrained 3-colorings


(Notice that the colorings are not up to isomorphism: all six vertices are considered to be distinct and not interchangeable.)


These solutions are found with a brute-force recursive search. The approach exemplifies a large class of problems, such as playing games and solving puzzles. In most interesting cases the search can take a long time (and have a large amount of output), so it is important to find appropriate data structures and efficient search methods. I am interested in Mathematica-specific advice and strategies for making such searches efficient.


To make this question clearer and more focused, I invite your critical comments concerning this particular solution to the constrained $n$-coloring problem:


constrainedColorings[graph[vertices_, nbrhds_], colors_List, start_List] := Module[

{unassigned, v, candidates},
unassigned = Complement[vertices, start[[All, 1]]];
If[unassigned == {}, Return[start]];
v = First[unassigned];
candidates = Complement[colors, v /. nbrhds /. start];
Map[constrainedColorings[graph[vertices, nbrhds], colors, Append[start, v -> #]] &, candidates]
];

Its arguments are





  • graph, which contains a list of the vertices and a list of rules assigning to each vertex the set of its immediate neighbors in the graph;




  • colors, which is a list of the available colors; and




  • start, which is a (possibly empty) list of rules assigning vertices to colors: it stipulates any constraints. It is expected that the colors appearing in start are contained within colors.





Its output is a deeply nested list (representing the search tree) whose leaves are lists of rules assigning colors to vertices.


Like most such searches, it follows a familiar logic:




  1. Determine whether the search is finished.




  2. If not, make a list of possible next moves (candidates),





  3. ... and tentatively make each move in turn, recursively searching for all solutions arising from it.




  4. Return a set of all solutions found.




To illustrate its use, consider the preceding example. It started out as a Mathematica Graph (in order to exploit its graph visualization capabilities) and was converted into a more convenient graph structure for this search:


\[Gamma] = Graph[{v1, v2, v3, v4, v5}, 
{v1 \[UndirectedEdge] v2, v1 \[UndirectedEdge] v4, v1 \[UndirectedEdge] v5,
v2 \[UndirectedEdge] v3, v3 \[UndirectedEdge] v4, v3 \[UndirectedEdge] v5},

VertexShapeFunction -> "Circle", VertexSize -> 0.4];
g = graph[VertexList[\[Gamma]], # -> Cases[EdgeList[\[Gamma]],
# \[UndirectedEdge] v_ | v_ \[UndirectedEdge] # -> v] & /@ VertexList[\[Gamma]]];

Here is the search itself, whereby the available colors are stipulated and the initial constraints are provided:


colorings = constrainedColorings[g, {Red, Green, Blue}, {v5 -> Red}];

We can flatten the output to get a list of all solutions:


colorings /. x : List[_Rule ..] :> coloring @@ x // Flatten


If you care to play with this code, you will want to draw the output:


display[g_Graph, c_coloring] :=  HighlightGraph[g, List @@ c /. Rule -> Style];
display[\[Gamma], #] & /@ colorings

Here, then, is the specific question:



  • In what ways can this code be improved to be faster, simpler, and more flexible?


I am especially interested in advice that would apply not just to this particular problem but to the entire class of problems. What kinds of data structures should one prefer to represent combinatorial objects: arrays, rules, something else? Or perhaps there is no general answer? Are there ways to expedite such searches, such as (possibly) exploiting Mathematica's built-in graph programming capabilities?


General replies are fine and so are answers that specifically improve the code here, provided it is clear how such improvements could be applied more generally.




Answer



One can also go about this using integer linear programming, with an array of 0-1 variables indexed by vertices and colors. Here is one encoding of that approach.


constrainedColorings2[graph[vertices_, nbrhds_], colors_List, 
start_List, v_] := Module[
{unassigned, nv = Length[vertices], nc = Length[colors], vars,
fvars, c1, c2, c3, c4, pos1, pos2, constraints, solns},
vars = Array[v, {nv, nc}];
fvars = Flatten[vars];
c1 = Map[0 <= # <= 1 &, fvars];
c2 = Map[Total[#] == 1 &, vars];

c3 = Map[Table[
pos1 = Position[vertices, #[[1]]][[1, 1]];
pos2 = Position[vertices, #[[2, j]]][[1, 1]];
v[pos1, k] + v[pos2, k] <= 1, {k, nc}, {j, Length[#[[2]]]}] &,
nbrhds];
c4 = Map[(pos1 = Position[vertices, #[[1]]][[1, 1]];
pos2 = Position[colors, #[[2]]][[1, 1]];
v[pos1, pos2] == 1
) &, start];
constraints = Flatten[Join[c1, c2, c3, c4]];

solns = Solve[constraints, fvars, Integers];
Map[Thread[vertices -> ((vars /. #).colors)] &, solns]
]

Your example, slightly altered (I'm not getting the graphing right and don't have time for that now) looks like this.


c2 = 
constrainedColorings2[g, {rRed, gGreen, bBlue}, {v5 -> rRed}, v]

(* Out[220]= {{v1 -> bBlue, v2 -> gGreen, v3 -> bBlue, v4 -> gGreen,
v5 -> rRed}, {v1 -> bBlue, v2 -> gGreen, v3 -> bBlue, v4 -> rRed,

v5 -> rRed}, {v1 -> bBlue, v2 -> rRed, v3 -> bBlue, v4 -> gGreen,
v5 -> rRed}, {v1 -> bBlue, v2 -> rRed, v3 -> bBlue, v4 -> rRed,
v5 -> rRed}, {v1 -> bBlue, v2 -> rRed, v3 -> gGreen, v4 -> rRed,
v5 -> rRed}, {v1 -> gGreen, v2 -> bBlue, v3 -> gGreen, v4 -> bBlue,
v5 -> rRed}, {v1 -> gGreen, v2 -> bBlue, v3 -> gGreen, v4 -> rRed,
v5 -> rRed}, {v1 -> gGreen, v2 -> rRed, v3 -> bBlue, v4 -> rRed,
v5 -> rRed}, {v1 -> gGreen, v2 -> rRed, v3 -> gGreen, v4 -> bBlue,
v5 -> rRed}, {v1 -> gGreen, v2 -> rRed, v3 -> gGreen, v4 -> rRed,
v5 -> rRed}} *)

Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...