Skip to main content

graphics - BarChart FrameLabels with only partial Frame?


This test BarChart is generated by the code that follows it:


enter image description here


data = Table[RandomInteger[{1, 10}], {3}, {4}];


BarChart[MapThread[Labeled[#1, #2, Above] &, {data, {1, 2, 3}}],
ChartLayout -> "Stacked",
ChartStyle ->
Reverse@{Lighter@Blue, Blue, Darker@Blue, Darker@Darker@Blue},
ChartLabels -> {{"a", "b", "c"}, None},
Frame -> {False, True, False, False},
FrameLabel -> {"x axis", "y axis"},
BaseStyle -> {FontFamily -> "Helvetica", FontSize -> 14}]

Since only a y-axis component of Frame is rendered: Frame -> {False, True, False, False} the "x axis" label of FrameLabel -> {"x axis", "y axis"} is omitted - and that's consistent with documentation.



Is it possible to display "x axis" at the location it would be if the bottom component of the Frame were there and preserving the set BaseStyle values (eg Font, FontSize)?


This can be done using Inset but positioning is ad-hoc and it does not preserve BaseStyle values.


Wrapping Labeled around Barchart doesn't correctly center the text and moreover does not use the BaseStyle values, as the following screenshot shows. Here for comparison the bottom component of Frame is True - and note the disastrous clash of graphical elements.


enter image description here


Finally, using the bottom Frame component: Frame -> {True, True, False, False} but without ticks: FrameTicks -> {None, Automatic, None, None} results in an ugly double axis and overlap in labels:


enter image description here


Any other options, eg using LabelingFunction?



Answer



You can remove the overlaid ticks by using FrameTicksStyle to set them to Transparent and remove the doubled edge by setting PlotRangePadding to None, like so:


BarChart[MapThread[Labeled[#1, #2, Above] &, {data, {1, 2, 3}}], 

ChartLayout -> "Stacked",
ChartStyle ->
Reverse@{Lighter@Blue, Blue, Darker@Blue, Darker@Darker@Blue},
ChartLabels -> {{"a", "b", "c"}, None},
Frame -> {True, True, False, False},
FrameTicksStyle -> {Automatic, Transparent},
PlotRangePadding -> None, FrameLabel -> {"x axis", "y axis"},
BaseStyle -> {FontFamily -> "Helvetica", FontSize -> 14}]

Or you could explicitly set the FrameTicks to something invisible but that takes up the same vertical spacing you want, like so:



BarChart[MapThread[Labeled[#1, #2, Above] &, {data, {1, 2, 3}}], 
ChartLayout -> "Stacked",
ChartStyle ->
Reverse@{Lighter@Blue, Blue, Darker@Blue, Darker@Darker@Blue},
ChartLabels -> {{"a", "b", "c"}, None},
Frame -> {True, True, False, False},
FrameTicks -> {{Automatic, Automatic}, {{{1, ""}}, None}},
PlotRangePadding -> None, FrameLabel -> {"x axis", "y axis"},
BaseStyle -> {FontFamily -> "Helvetica", FontSize -> 14}]

Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.