Skip to main content

graphics - BarChart FrameLabels with only partial Frame?


This test BarChart is generated by the code that follows it:


enter image description here


data = Table[RandomInteger[{1, 10}], {3}, {4}];


BarChart[MapThread[Labeled[#1, #2, Above] &, {data, {1, 2, 3}}], 
 ChartLayout -> "Stacked", 
 ChartStyle -> 
  Reverse@{Lighter@Blue, Blue, Darker@Blue, Darker@Darker@Blue}, 
 ChartLabels -> {{"a", "b", "c"}, None},
 Frame -> {False, True, False, False},
 FrameLabel -> {"x axis", "y axis"}, 
 BaseStyle -> {FontFamily -> "Helvetica", FontSize -> 14}]

Since only a y-axis component of Frame is rendered: Frame -> {False, True, False, False} the "x axis" label of FrameLabel -> {"x axis", "y axis"} is omitted - and that's consistent with documentation.



Is it possible to display "x axis" at the location it would be if the bottom component of the Frame were there and preserving the set BaseStyle values (eg Font, FontSize)?


This can be done using Inset but positioning is ad-hoc and it does not preserve BaseStyle values.


Wrapping Labeled around Barchart doesn't correctly center the text and moreover does not use the BaseStyle values, as the following screenshot shows. Here for comparison the bottom component of Frame is True - and note the disastrous clash of graphical elements.


enter image description here


Finally, using the bottom Frame component: Frame -> {True, True, False, False} but without ticks: FrameTicks -> {None, Automatic, None, None} results in an ugly double axis and overlap in labels:


enter image description here


Any other options, eg using LabelingFunction?



Answer



You can remove the overlaid ticks by using FrameTicksStyle to set them to Transparent and remove the doubled edge by setting PlotRangePadding to None, like so:


BarChart[MapThread[Labeled[#1, #2, Above] &, {data, {1, 2, 3}}], 

 ChartLayout -> "Stacked", 
 ChartStyle -> 
  Reverse@{Lighter@Blue, Blue, Darker@Blue, Darker@Darker@Blue}, 
 ChartLabels -> {{"a", "b", "c"}, None}, 
 Frame -> {True, True, False, False}, 
 FrameTicksStyle -> {Automatic, Transparent}, 
 PlotRangePadding -> None, FrameLabel -> {"x axis", "y axis"}, 
 BaseStyle -> {FontFamily -> "Helvetica", FontSize -> 14}]

Or you could explicitly set the FrameTicks to something invisible but that takes up the same vertical spacing you want, like so:



BarChart[MapThread[Labeled[#1, #2, Above] &, {data, {1, 2, 3}}], 
 ChartLayout -> "Stacked", 
 ChartStyle -> 
  Reverse@{Lighter@Blue, Blue, Darker@Blue, Darker@Darker@Blue}, 
 ChartLabels -> {{"a", "b", "c"}, None}, 
 Frame -> {True, True, False, False}, 
 FrameTicks -> {{Automatic, Automatic}, {{{1, ""}}, None}}, 
 PlotRangePadding -> None, FrameLabel -> {"x axis", "y axis"}, 
 BaseStyle -> {FontFamily -> "Helvetica", FontSize -> 14}]

Comments

Post a Comment

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...
Post a Comment
Read more

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]
Post a Comment
Read more