Skip to main content

interoperability - How to trigger UNIX command-line command from Mathematica notebook?


At UNIX command line, one can run ls -la $HOME. How to trigger this from Mathematica notebooks?


Run["!ls -la $HOME"]



32512

Returns some integer -- what is it? -- but not the normal output.



Answer



The Run command returns the exit code of the program being run. In your case, the program is "!ls" which probably doesn't exist on your system (If you try


sh -c '!ls -la $HOME'

you'll also get an error). Why it returns 32512 instead of 127 (which is the return value I get by the shell) I don't know; however I notice that $32512 =127\cdot 256$, so I guess it's in order to better distinguish valid exit codes (usually telling about errors during the execution) from errors occurring when trying to execute the command (like not finding the executable).


If you start a raw kernel and type



Run["ls -la $HOME"]

(without exclamation mark) you'll see the output of the ls command on standard output, and a returned value of 0 (the exit code of ls). If you do it from a notebook, the standard out will be the one Mathematica was started with; if started from a terminal, that's where the output will happen, otherwise it will end up elsewhere or even nowhere (in my test, the directory listing ended up in .xsession-errors because I started Mathematica through the desktop environment).


If you are interested in the actual output, you have to use a file reading command, and use the special "!" syntax; for example Import as suggested by user18792,


Import["!ls -la $HOME", "Text"]

giving you all the output in a single string, or ReadList as suggested by Gustavo Delfino,


ReadList["!ls -la",String]

giving you a list of strings, each containing a single line of the output.



Note that the exclamation mark says you want to get the output of a command instead of the contents of a file (whose name would have gone at that point otherwise). That's why you don't put the exclamation mark at the Run command: Its argument is not a file to read, but already a command to execute, thus you don't need (and cannot use) the exclamation mark "escape" to use a command instead of a file.


If you need both the output and the exit code, apparently in version 10 you can use RunProcess (I can't check that because I don't have access to v10). From the documentation, I get that the command would look like the following:


RunProcess[{"ls", "-la", Environment["HOME"]}]

Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....