Skip to main content

code review - Numerical Integration Via Adaptive Simpson's Method


I have written a code that uses the Adaptive Simpson's method to approximate integration. For those who are unaware of this Adaptive Simpson's method; Adaptive Simpson's method


In my code, I count the number of function evaluations are needed. I am wondering if there is a way to reduce the number of function evaluations needed but still retaining the same outputs and error. Here is my code:


Simpson[f_, a_, b_, er_] := Module[{s1, s2, h2, h = (b - a)/2},

s1 = h (f[a] + 4 f[a + h] + f[b])/3;
h2 = h/2;
s2 = h2 (f[a] + 4 f[a + h2] + 2 f[a + h] + 4 f[b - h2] + f[b])/3;


If[Abs[s1 - s2]/15 < er, s2 + (s2 - s1)/15,
Simpson[f, a, a + h, er/2] + Simpson[f, a + h, b, er/2]]];
count = 0;
h[x_] := Module[{}, count++; 3 Sqrt[x]];
N[Simpson[h, 0, 1, 10.^-5] - 2]
count

For example, when approximating the integral of $3*sqrt(x)$ from 0 to 1, my algorithm makes 312 function calls of the function h, but I suspect some of these evaluations are repeated.



Answer




With a simple modification to your code


Simpson[f_, a_, b_, er_] := 
Module[{s1, s2, h2, h = (b - a)/2},
s1 = h (f[a] + 4 f[a + h] + f[b])/3;
h2 = h/2;
s2 = h2 (f[a] + 4 f[a + h2] + 2 f[a + h] + 4 f[b - h2] + f[b])/3;
If[Abs[s1 - s2]/15 < er, s2 + (s2 - s1)/15,
Simpson[f, a, a + h, er/2] + Simpson[f, a + h, b, er/2]]];
count = 0;
h[x_] := Module[{}, Sow[x]; count++; 3 Sqrt[x]];

{result, xvalues} = Reap[N[Simpson[h, 0, 1, 10.^-5] - 2]];
{Length[Union[Flatten[xvalues]]], count}
(* {81, 312} *)

we can see that indeed your code evaluates h 312 times but at only 81 distinct values.


If the execution time of the integration is dominated by evaluating h this is clearly undesirable. A simple fix is to use "memoisation". This avoids re-evaluating h for values of x where it has already been computed. This can easily be done by using a definition for h such as


h[x_]:=h[x]= 3 Sqrt[x]

There is a very clear discussion of this in the Mathematica documentation https://reference.wolfram.com/language/tutorial/FunctionsThatRememberValuesTheyHaveFound.html


Comments

Popular posts from this blog

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...