performance tuning - Split a string at specific positions

Given a string of alphanumerical characters, how to split it simply and quickly at the center of continuous letter-substrings? Is there an elegant and fast solutions out there in the "computational universe"?

The splitter should create "syllables" with one digit as a nucleus for each syllable, that is, at the end there should be only one digit per sublist. When there are more letter characters between digits, letters should be shared by the bordering digits (here I simulated a half share, distributing towards the right bordering digit in case of an odd number of letters), and starting and ending letter-sequences should be just attached to the closest digit.

"xxx00xxx000x0xx0xxxx000xx0xx" (* original string *)


"xxx0 | 0x | xx0 | 0 | 0 | x0x | x0xx | xx0 | 0 | 0x | x0xx" (* intermediate *)

{"xxx0", "0x", "xx0", "0", "0", "x0x", "x0xx", "xx0", "0", "0x", "x0xx"} (* end *)

Note that the string never contains spaces by default.

Answer

Here is a faster version of István's function:

split[s_String] :=
  StringReplace[s, {
    StartOfString ~~ l : LetterCharacter .. :> l,

    l : LetterCharacter .. ~~ EndOfString   :> l,
    l : LetterCharacter .. :>
          StringInsert[l, " ", 1 + Quotient[StringLength@l, 2] ],
    d : Repeated[DigitCharacter, {2, ∞}] :>
          StringJoin @ Riffle[Characters@d, " "]
  }] // StringSplit

Timings:

str = StringJoin @@ (RandomInteger[{0, 1}, {500000}] /. {0 -> "0", 1 -> "x"});


First@AbsoluteTiming[istvan = splitIstvan@str;]
First@AbsoluteTiming[mrwizard = split@str;]
istvan === mrwizard

0.7710441

0.4260243

True

Comments

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

Blog

Search This Blog